/************************************
    Author: PUT YOUR NAME HERE
    Date created: 18 Aug 2020
    Date last modified: 18 Aug 2020
    Program: stringPlay.py
 
************************************/

/*****************sample solution**********
***************Problem 0******************/
public class StringFunctions
{
    /* arg is a string in which the specified letter occurs
    at least twice, letter is a one-character string
    this function returns a new string with the characters
    between the first and last instance of letter in the string*/
    public static String get_between(String arg, char letter)
    {
        int start = arg.indexOf(letter);
        int end = arg.lastIndexOf(letter);
        return arg.substring(start + 1, end);
    }
    //You have a solution  manual.  Look in the main
    //method for a sample test.
    //Create at least one for each function.
    /***************Problem 1*****************
    arg is a string, letter is a one-character string
    remove all instances of letter from arg, both upper and 
    lower case*/
    public static String remove_letter(String arg, char letter)
    {
        return "";
    }
    /***************Problem 2*****************
    /*arg is guaranteed to have at least two letters
    and to be an alphabetical string
    return a string with the first and last letters of arg.*/
    public static String eviscerate(String arg, char letter)
    {
        return "";
    }
    
    /***************Problem 3*****************
    /*head has an even number of letters
    tail has an even number of letters
    return a string whose first half is the first
    half of head and the second half of tail.*/
    public static String frankenstein(String head, String tail)
    {
        return "";
    }
    /***************Problem 4*****************
    arg is a string, letter is a character 
    returns the number of times letter appeaers in arg, case
    insensitive */
    public static int letter_count(String arg, char letter)
    {
        return 0;
    }
    
    /***************Problem 5*****************
   "arg is a string, letter is a one-character
    string, and n is an integer 0 <= n <= len(letter)
    return the number of instances of letter in the
    first n characters of the string arg*/
    public static int letter_count_partial(String arg, char letter, int n)
    {
        return 0;
    }
    
    
    /****************Problem 6*****************
        """arg is a string, ch is a one-character string
    and n is an integer, n >= 0
    returns the string arg centered in a string of length
    n, padded  with character ch.  If n < len(arg), it just
    returns arg(no conditional logic on your part needed)*/
    public static String marquee(String arg, char ch, int n)
    {
        return "";
    }
    
    /***************Problem 7*****************
        arg is any string
    get rid of all of the whitespace on the left, if any
    replace any spaces on the right with ch and return 
    the result.*/
    public static String doodle(String arg, char ch)
    {
        return "";
    }
    public static void main(String[] args)
    {
        String arg = "quoque";
        char letter = 'q';
        String result = "uo";
        System.out.println(result.equals(get_between(arg, letter))? "PASS":"FAIL");
        arg  = "robber";
        letter = 'r';
        result = "obbe";
        System.out.println(result.equals(get_between(arg, letter))? "PASS":"FAIL");
        //possible grist for a test case, problem 1
        arg = "Sissyphus";
        result = "iyphu";
        //grist for test on #2
        //
        arg = "heinous";
        result = "hs";
        arg = "Washington";
        result = "Wn";
        //test #3
        String head = "cerebellum";
        String tail = "wagger";
        result = "cereger";
    
        //test grist. #4
        arg = "Babbage";
        letter = 'b';
        int count = 3;
        //grist for testing, #5
        arg = "Babbage";
        count = 3;
        arg = "flibbertygibbet";
        count = 2;

         //* test grist, #6 Make it work like Python
        arg = "wabbit";
        result = "!!!!!!!!!!!!wabbit!!!!!!!!!!!!";
        
        //test grist, #7  Make it work like Python
        arg = "        wabbit    ";
        result = "wabbit@@@@";
    }
}