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# Author: PUT YOUR NAME HERE
#  Date created: 18 Aug 2020
#  Date last modified: 18 Aug 2020
#  Program: stringPlay.py
# 
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################sample solution##########
###############Problem 0#################
def get_between(arg, letter):
    """precondition: arg is a string in which the specified letter occurs
at least twice, letter is a one-character string
postcondition: this function returns a new string with the characters
between the first and last instance of letter in the string """
    start = arg.find(letter)
    end = arg.rfind(letter)
    return arg[start + 1: end]
##You have a solution  manual.  Generate some test cases
##as seen here.  Create at least one for each function.
arg = "quoque"
letter = "q"
result = "uo"
print("PASS" if result == get_between(arg, letter) else "FAIL")
arg = "robber"
letter = "r"
result = "obbe"
print("PASS" if result == get_between(arg, letter) else "FAIL")

###############Problem 1#################
def remove_letter(arg, letter):
    """arg is a string, letter is a one-character string
remove all instances of letter from arg, both upper and 
lower case"""
    pass
#possible grist for a test case....
arg = "Sissyphus"
# your code goes here.
result = "iyphu"

###############Problem 2#################
def eviscerate(arg, letter):
    """arg is guaranteed to have at least two letters
and to be an alphabetical string
return a string with the first and last letters of arg."""
    pass

##grist for testing
arg = "heinous"
result = "hs"

##grist for testing
arg = "Washington"
result = "Wn"

###############Problem 3#################
def frankenstein(head, tail):
    """head has an even number of letters
tail has an even number of letters
return a string whose first half is the first
half of head and the second half of tail."""

##test grist
head = "cerebellum"
tail = "wagger"
result = "cereger"

###############Problem 4#################
def letter_count(arg, letter):
    """ arg is a string, letter is a one-character string
returns the number of times letter appeaers in arg, case
insensitive"""

##test grist.
arg = "Babbage"
result = 3

###############Problem 5#################
def letter_count_partial(arg, letter, n):
    """arg is a string, letter is a one-character
string, and n is an integer 0 <= n <= len(letter)
return the number of instances of letter in the
first n characters of the string arg"""
    pass
##grist for testing.
arg = "Babbage"
result = 3

arg = "flibbertygibbet"
result = 2

###############Problem 6#################
def marquee(arg, ch, n):
    """arg is a string, ch is a one-character string
and n is an integer, n >= 0
returns the string arg centered in a string of length
n, padded  with character ch.  If n < len(arg), it just
returns arg(no conditional logi on your part needed)"""
    pass
 # test grist
arg = "wabbit"
result = "!!!!!!!!!!!!wabbit!!!!!!!!!!!!"

###############Problem 7#################
def doodle(arg, ch):
    """arg is any string
get rid of all of the whitespace on the left, if any
replace any spaces on the right with ch and return 
the result."""
    pass
#test grist
arg = "        wabbit    "
result = "wabbit@@@@"